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9x^2+101x+222=0
a = 9; b = 101; c = +222;
Δ = b2-4ac
Δ = 1012-4·9·222
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(101)-47}{2*9}=\frac{-148}{18} =-8+2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(101)+47}{2*9}=\frac{-54}{18} =-3 $
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